Draw the angle given in degrees on the unit circle where 0 radians corresponds to the positive portion of the horizontal axis: -16pi/7
anyone ?
plz help me
plz help me
\(\bf \cfrac{16}{7}\implies \cfrac{7+7+2}{7}\implies \cfrac{\cancel{7}}{\cancel{7}}+\cfrac{\cancel{7}}{\cancel{7}}+\cfrac{2}{7}\implies 1+1+\cfrac{2}{7} \\ \quad \\ 2+\cfrac{2}{7} \\ \quad \\ thus\qquad -\cfrac{16}{7}\implies -2\pi -\cfrac{2\pi }{7}\) notice, a full CLOCKWISE cycle is \(-2\pi\) so just draw the remaining after the cycle and then get the CLOCKWISE angle
shoot... actually that's backwards
notice, a full CLOCKWISE cycle is −2π so just draw the remaining after the cycle and then get the COUNTER-CLOCKWISE angle
anyhow \(\bf -\cfrac{16\pi }{7}\implies -2\pi -\cfrac{2\pi }{7}\)
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