Question

@Hero

Answer 1

its 100

Answer 2

The sum of an infinite geometric series is:

\(\Large S_{\infty} = \dfrac{a_1}{1 - r}\)

where \(a_1\) is the first term, and r is the common ratio.

Answer 3

We have \(a_1 = 40\), and \(r = \dfrac{3}{5} \)

\(\Large S_{\infty} = \dfrac{a_1}{1 - r}\)

\(\Large S_{\infty} = \dfrac{40}{1 - \frac{3}{5}} = \dfrac{40}{\frac{2}{5}} = \dfrac{40\times5}{2} = 100\)

Answer 4

You are correct.