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OpenStudy (anonymous):
Fan and Medal
Im confused please help
Solve: 5x2 + 25x = 0.
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OpenStudy (anonymous):
How would I get this into quadratic formula without a c variable
OpenStudy (anonymous):
@jim_thompson5910 @Vocaloid @Hero
OpenStudy (anonymous):
Then you do not use c at all
The 4ac becomes 0 in the equation.
OpenStudy (anonymous):
out of my answer choices what would it be then? I'm confused at how you would plug it in and still get the answer
OpenStudy (anonymous):
x = 0, x = 5
x = 0, x = −5
x = −5, x = 0, x = 5
x = 5, x = 25
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OpenStudy (anonymous):
-b\[\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
OpenStudy (anonymous):
ax^2+bx+c
so a=5 and b=25
OpenStudy (anonymous):
so it would be -25 =+/- sqrt of 25 all over 10
OpenStudy (anonymous):
i got it thanks
OpenStudy (anonymous):
\[\frac{ -25\pm \sqrt{25^2-4(5)(0)} }{ 2(5) }\]
\[\frac{ -25\pm \sqrt{625} }{ 10 }\]
\[\frac{ -25\pm25 }{ 10 }\]
using addition it is \[\frac{ -25+25 }{ 10 }=0\]
using subtraction it is \[\frac{ -25-25 }{ 10}=-5\]
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OpenStudy (anonymous):
Glad you did :)
OpenStudy (anonymous):
wait it is not square root of 25. You mean square root of 625 since it is b^2 not b
OpenStudy (jack1):
all good now?
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