Question

help plz

Answer 1

Explain the difference between using the sine ratio to solve for a missing angle in a right triangle versus using the cosecant ratio. You must use complete sentences and any evidence needed (such as an example) to prove your point of view.

Answer 2

@surjithayer can you help me plz

Answer 3

@misty1212

Answer 4

Explain the difference between using the sine ratio to solve for a missing angle in a right triangle versus using the cosecant ratio. You must use complete sentences and any evidence needed (such as an example) to prove your point of view.

Answer 5

HI!!

Answer 6

one is the reciprocal of the other

Answer 7

hi can you help me plz

Answer 8

but if you are looking for an angle, you really have to use sine
lets give an example

Answer 9

suppose we are looking for angle \(x\)

Answer 10

it asking the dfference

Answer 11

ok

Answer 12

then you have \[\sin(x)=\frac{5}{7}\] and you also have \[\csc(x)=\frac{7}{5}\]

Answer 13

but you want the angle, so you have to use the inverse trig function to find it

Answer 14

yess

Answer 15

\[\sin(x)=\frac{5}{7}\\
\sin^{-1}(\frac{5}{7})=x\] you would use a calculator to get than number

Answer 16

but no calculator has an inverse cosecant on it,so you would not be able to find \[\csc^{-1}(\frac{7}{5})\] so get \(x\)

Answer 17

you would have to use the inverse sine (sometimes called the "arcsine") that is the only way you could do it

Answer 18

okay so the difference is that sine you can use inverse and cse u can't

Answer 19

yes

Answer 20

thanks

Answer 21

\[\color\magenta\heartsuit\]