Question

i need help on a math problem

Answer 1

heres what is looks like

Answer 2

solve for x

Answer 3

does that say square root of x +4-3=1

Answer 4

thats a minus not a division my bad really bad at drawing

Answer 5

I'm sorry, I'm still not following. Can you type the problem out please.

Answer 6

\[\sqrt{4}-3=1\]

Answer 7

sorry typed wrong\[\sqrt{X+4}-3=1\]

Answer 8

ok! got it...to solve for x, you have to get x by itself.

Answer 9

start by moving what's outside of the radical to the other side..

Answer 10

i need to know how like the steps please

Answer 11

\[\sqrt{x+4}-3=1\] get rid of the 3 on the left side of the equation, by adding 3 to both sides. so..\[\sqrt{x+4}-3+3=1+3\]

Answer 12

now you have\[\sqrt{x+4}=4\]

Answer 13

what next please

Answer 14

next deal with the square root...how do you think you "undo" a square root?

Answer 15

subtract another square root idk

Answer 16

ok, try this...what's \[\sqrt{25}\]

Answer 17

5

Answer 18

oh so do you just simplify it

Answer 19

ok, so square root of 25 is 5...how do you get it back to 25?

Answer 20

5*5

Answer 21

times

Answer 22

perfect! you squared it! so to undo a square root you square it!

Answer 23

5 times 5

Answer 24

\[\sqrt{x+4}^{2}=4^{2}\]

Answer 25

16

Answer 26

by raising the square root to a power of 2, you pretty much undo it all so you're left with x+4=16

Answer 27

solve for x

Answer 28

12

Answer 29

@nigel305 , what do you think?

Answer 30

thanks lol

Answer 31

simplier

Answer 32

I need a medal since i help

Answer 33

sorry cant she was first