3x^2-x-4=0

Question

3x^2-x-4=0

misty1212 · Answer

they really got you factoring, don't they?

anonymous · Answer

yes i took algebra 3 and this is all we are doing is factoring

misty1212 · Answer

algebra 3? i didnt know they had that many algebras?

anonymous · Answer

neither did i until i went to this school

misty1212 · Answer

try $$(3x-4)(x+1)=0$$

arindameducationusc · Answer

You can use quadratic equation also.....

misty1212 · Answer

sure but that is more complicated, my guess is since one factors, they all factor

arindameducationusc · Answer

I agree with Misty's factorisation...... that's more easy....

misty1212 · Answer

do you know what to do once you have $$(3x-4)(x+1)=0$$?

anonymous · Answer

it worked thank you @misty1212

misty1212 · Answer

$$\color\magenta\heartsuit$$

anonymous · Answer

i have one more problem if you don't mind helping :)

misty1212 · Answer

not at all happy to

anonymous · Answer

$$6x^2-13x+6=0$$

misty1212 · Answer

bet we can factor this one too huh?

anonymous · Answer

yeah pretty sure . my problem is trying to figure out what plus what would equal them middle number , and that would also equal the last number if multiplied

misty1212 · Answer

$$(2 x-3) (3 x-2) = 0$$ seems to work

arindameducationusc · Answer

attachment

arindameducationusc · Answer

use this b=-13 a=6 and c=6

misty1212 · Answer

it is not that easy to figure out
people claim they have methods, but the methods amount to trial an error anyways

misty1212 · Answer

that is why i like to cheat
makes life easier
this is all donkey work anyways

anonymous · Answer

thank you so much for the help :)