Question

Factor the polynomials:m^3+1/8 and p^3+216

Answer 1

Hey :)

Answer 2

\[\large\rm m^3+\frac{1}{8}\]Hmmm, recall that we have a rule for factoring the `sum of cubes`:
\[\large\rm a^3+b^2=(a+b)(a^2-ab+b^2)\]

Answer 3

But with the way our problem is written right now,
we only have one cube.

Any ideas how to turn the 1/8 into `something`^3 ?

Answer 4

@August899

Answer 5

do we divide 1 over 8?

Answer 6

The 8 is some number to the third power.

Answer 7

Example: 27 is 3 to the third power.
Because 3 x 3 x 3 = 27
Therefore \(\large\rm 27=3^3\)

Answer 8

Comeon Auguuuuuust >.<
break down the 8, how can we write that another way?