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Mathematics
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imqwerty (imqwerty):
Fun question
11 years ago
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OpenStudy (hayleymeyer):
type faster! XD
11 years ago
imqwerty (imqwerty):
originally posted by @ParthKohli
Find the value of \[\sum_{n=1}^{\infty}\frac{F(n)}{2^n}\]
where F(n)=n th term of fabronici series
11 years ago
OpenStudy (anonymous):
OOOOO the answer is...... something :D am i right?
11 years ago
OpenStudy (hayleymeyer):
is that u tash?
11 years ago
OpenStudy (anonymous):
Who else would be this smart
11 years ago
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OpenStudy (hayleymeyer):
*giggels* XD
11 years ago
OpenStudy (anonymous):
XD I know what seba looks like....
11 years ago
OpenStudy (anonymous):
Yah..... that question is way to hard..... Is it Calculus?
11 years ago
ganeshie8 (ganeshie8):
\[\sum_{n=0}^\infty F_nx^n = \frac{1}{1-x-x^2}\]
plugin \(x = \frac{1}{2}\)
11 years ago
imqwerty (imqwerty):
:D do u knw the derivation of this thing? :)
11 years ago
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ganeshie8 (ganeshie8):
derivation is pretty easy, there are hundreds of web pages that has this derivation...
11 years ago
imqwerty (imqwerty):
i'll post a better fun question @ganeshie8 aka geniusie8
11 years ago
imqwerty (imqwerty):
:D
11 years ago
ganeshie8 (ganeshie8):
questions relating to fibonacci sequence are fun indeed! try this when you're free :
\[\large \lim\limits_{n\to\infty}\dfrac{F_{n+1}}{F_n} ~~=~~\phi\]
where \(\phi\) is the golden ratio.
11 years ago
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imqwerty (imqwerty):
thanks @ganeshie8
11 years ago
Parth (parthkohli):
Hey, I posted that on PA.
11 years ago
imqwerty (imqwerty):
lol
11 years ago
Parth (parthkohli):
\[\lim_{n \to \infty } \frac{F_{n+1}}{F_n} = L \]\[= \lim_{n\to \infty} \frac{F_n}{F_n} + \lim_{n \to \infty} \frac{F_{n-1}}{F_n}\]\[= 1 + \frac{1}{L}\]
11 years ago
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