Question

A solution of aqueous Calcium hydroxide (1050.0 g) was formed by dissolving solid Calcium hydroxide in water (725 g). If the density of the solution is 1.45 g/mL, calculate the following:

Answer 1

Mass Percent of Calcium hydroxide 59.2

parts per million of Calcium hydroxide 592000

molality 19.59

Molarity 19.59

Mole Fraction of Calcium hydroxide (Calculate this answer. Don't find it by subtracting the solvent's X from 1) 0.5915

Mole Fraction of Water (Calculate this answer. Don't find it by subtracting the solute's X from 1) 0.4366

Answer 2

The answers I came up with are next to the problems, however they are incorrect.

Answer 3

@welshfella

Answer 4

i gotta go rihgt now sorry

Answer 5

Alright.

Answer 6

@mathmate @inkyvoyd @surjithayer @Luigi0210 @dan815

Answer 7

@radar @whpalmer4 @peachpi

Answer 8

Are you sure the question said calcium hydroxide?

The solubility of Ca(OH)2 is less than 0.2 g/100 ml in aqueous H2O, so it is impossible to have a density of 1.45g/mL.
Do you mean 1050.0 g of Ca(OH)2 dissolved in 725 g of water, or 725 g of Ca(OH)2 dissolved in water to form 1050 g of solution? (It doesn't dissolve either way). It will not make a solution, but just a suspension (for whitewashing walls!)

Perhaps NaOH or KOH would have that kind of solubility.

Answer 9

That's exactly what the question said @mathmate. Do you see where I went wrong in my calculations?

Answer 10

@Nnesha @zepdrix @Compassionate

Answer 11

first sort out the given data
it says the aqueous solution was 1050g which means that 1050g has water and Ca(OH)2 both.
And they have said mass of water in that is 725g
Since they have asked for the mass percentage we have to calculate the mass of Ca(OH)2 in the solution that would be 1050-725 agree?
So the mass of Ca(OJ)2 would be 325g
Now calculate the mass percentage.
\[\frac{ 325 }{ 1050 }* 100% =30.95%\]

Answer 12

the answer i got was 30.95 %

Answer 13

@lena772
IMHO, the question went wrong, not you! lol