OpenStudy (anonymous):

a=[bx - c]= d

OpenStudy (anonymous):

some details please

OpenStudy (anonymous):

solve each question for x

OpenStudy (anonymous):

i already did it but i'm not sure if it's correct

OpenStudy (freckles):

do the brackets mean anything and you do know you have two equal signs right?

OpenStudy (anonymous):

is this some kind of algebra or something more exotic,and as freckles said do the brackets have some special you know meaning

OpenStudy (anonymous):

i think i wrote it wrong it's supposed to be a [bx -c] = d

OpenStudy (freckles):

welll okay I would divide both sides by a first isolating the thing in brackets

OpenStudy (freckles):

and put a little note on the side I suppose saying assuming a is not 0

OpenStudy (freckles):

bx-c=d/a then just undo the subtract by c by adding c on both sides

OpenStudy (freckles):

and then divide both sides by b making an assumption that b isn't 0

OpenStudy (anonymous):

i did this a [bx - c] =d divide both sides by a then [bx -c] =da bx-c =da then i add c on both sides bx=da+c over b x=da + c over b

OpenStudy (freckles):

if you divided both sides by a then why does it show you divided a on one side and multiplied a on the opposing side?

OpenStudy (freckles):

\[a(bx-c)=d \\ \\ \text{ divide } a \text{ on both sides assuming } a \neq 0 \\bx-c=\frac{d}{a} \\ \text{ adding } c \text{ on both sides } bx=c+\frac{d}{a} \\ \text{ now dividing } b \text{ on both sides assuming } b \neq 0 \\ x=\frac{1}{b}(c+\frac{d}{a})\]

OpenStudy (anonymous):

if i divide it, i have to put it as a fraction then?

OpenStudy (freckles):

things you divide by are things that go in the bottom like pretend we have m=3 and we wanted to divide both sides by 2 you can write that as: \[\frac{1}{2}m=\frac{1}{2}(3) \\ \text{ or } \frac{m}{2}=\frac{3}{2}\]

OpenStudy (anonymous):

yes i know but i wasnt sure about letters

OpenStudy (freckles):

the letters represent numbers

OpenStudy (anonymous):

words

OpenStudy (freckles):

they are to be treated just like numbers

OpenStudy (anonymous):

ok thanks