a=[bx - c]= d
some details please
solve each question for x
i already did it but i'm not sure if it's correct
do the brackets mean anything and you do know you have two equal signs right?
is this some kind of algebra or something more exotic,and as freckles said do the brackets have some special you know meaning
i think i wrote it wrong it's supposed to be a [bx -c] = d
welll okay I would divide both sides by a first isolating the thing in brackets
and put a little note on the side I suppose saying assuming a is not 0
bx-c=d/a then just undo the subtract by c by adding c on both sides
and then divide both sides by b making an assumption that b isn't 0
i did this a [bx - c] =d divide both sides by a then [bx -c] =da bx-c =da then i add c on both sides bx=da+c over b x=da + c over b
if you divided both sides by a then why does it show you divided a on one side and multiplied a on the opposing side?
\[a(bx-c)=d \\ \\ \text{ divide } a \text{ on both sides assuming } a \neq 0 \\bx-c=\frac{d}{a} \\ \text{ adding } c \text{ on both sides } bx=c+\frac{d}{a} \\ \text{ now dividing } b \text{ on both sides assuming } b \neq 0 \\ x=\frac{1}{b}(c+\frac{d}{a})\]
if i divide it, i have to put it as a fraction then?
things you divide by are things that go in the bottom like pretend we have m=3 and we wanted to divide both sides by 2 you can write that as: \[\frac{1}{2}m=\frac{1}{2}(3) \\ \text{ or } \frac{m}{2}=\frac{3}{2}\]
yes i know but i wasnt sure about letters
the letters represent numbers
words
they are to be treated just like numbers
ok thanks
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