Question

Counting question

Answer 1

\(\large \color{black}{\begin{align}
& \normalsize \text{How many triangles can be formed from 6 given points on a circle} \hspace{.33em}\\~\\
& a.)\ 6! \hspace{.33em}\\~\\
& b.)\ 3! \hspace{.33em}\\~\\
& c.)\ \dfrac{6!}{3!} \hspace{.33em}\\~\\
& d.)\ \dfrac{5\times 6\times 4}{6} \hspace{.33em}\\~\\
\end{align}}\)

Answer 2

by induction, on the number of points, I think that we can get:
\[\Large \left( {\begin{array}{*{20}{c}}
6 \\
3
\end{array}} \right)\]
triangles

Answer 3

so d?

Answer 4

yes!

Answer 5

answer given is d.)

Answer 6

thank vermuch

Answer 7

:)

Answer 8

dern just missed it didn't I?

Answer 9

any 3 chosen points will make a triangle

Answer 10

you need 3 different points

Answer 11

so 6 choose 3

Answer 12

what if it asked quadrilaterals 6C4 ?

Answer 13

yep

Answer 14

just gotta be careful though

Answer 15

that the points arent colinear

Answer 16

it should say in this question too that no 3 points are collinear

Answer 17

oh wait it says on a circle xD