Question

m=0 through (-9,1)

Answer 1

Graph the line

Answer 2

m= slope
so first write the equation
y=mx+b
where m is slope and b is y-intercept
substitute x and y for (-9,1) point

Answer 3

remember
x =something you would draw vertical line (undefined slope
when slope is zero you would draw horizontal line

Answer 4

if the slope is 0
that means that \(y_2 = y_1\) so that \(y_2-y_1 = 0\)
and that only occurrs on a horizontal line

Answer 5

So i know when its 0 its undefined and undefined is vertical line so i just graph it??

Answer 6

when the slope is zero it wouldn't be undefined

Answer 7

vertical line = undefined slope
horizontal line = (slope =0)

Answer 8

ok so how do i graph this question

Answer 9

\[\huge\rm \color{reD}{y} = m\color{red}{x}+b\]
replace m with 0
and (x,y) with the point (-9, 1) solve for b

Answer 10

\(slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies
\cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}\implies \cfrac{0}{something}\implies 0\impliedby defined
\\ \quad \\

\begin{array}{ccllll}
x&y
\\\hline\\
-9&1\\
-1000&1\\
+1000&1\\
\pm \infty&1
\end{array}\qquad y=1\impliedby \textit{horizontal line}\)

Answer 11

so infinity 1? i dont get the points D:

Answer 12

\[\rm \frac{ someting }{0 }=undefined \]

Answer 13

points ? what do you mean ? srry

Answer 14

i have to graph it and to graph u need at least 2 points

Answer 15

you can write an equation with one point and slope \[\huge\rm \color{reD}{y} = m\color{blue}{x}+b\]
\[\huge\rm (\color{blue}{x},\color{reD}{y})=(\color{blue}{-9},\color{red}{1})\]

Answer 16

substitute y for 1
and x for -9
m=0 \[\huge\rm \color{reD}{1}=-9(\color{blue}{0})+b\] (b is y-intercept)
solve for b

Answer 17

1

Answer 18

yes right
so now we should plugthem into the original equation of slope intercept form \[\huge\rm y=0x+1\]
0 times x= 0
so you have left with y =1 that's what you should graph

Answer 19

this one is pretty simple slope is 0 just draw a horizontal line where y =1