Question

Simplify the expression

Answer 1

\[(x ^{10}y^-5)^{1/5}\div(x^2y^3)^{1/3}\]

Answer 2

My answer is \[x^{4/3}\div2y\]

Answer 3

mhm

Answer 4

\[\huge\rm (xy)^m = x^m \times y^m\]remember this exponent rule
x and y both raising to the m power

Answer 5

Which is what I did

Answer 6

The top became (x^2y^-1). I put the y on the bottom because it's negative. The bottom was (x^2/3y).

Answer 7

have you got the right answer?

Answer 8

is -5 is the power of y?

Answer 9

sorry my internet gt disconnected yesterday.

Answer 10

\(\color{blue}{\text{Originally Posted by}}\) @ducksonquack
The top became (x^2y^-1). I put the y on the bottom because it's negative. The bottom was (x^2/3y).
\(\color{blue}{\text{End of Quote}}\)
how did you get 3 coefficient at the bottom ?

Answer 11

\[\huge\rm \frac{ x^2 y^{-1} }{ x^{2 \times \frac{ 1 }{ 3 }} y^{\cancel{3} \times \frac{ 1 }{ \cancel{3}} } }\]

Answer 12

ahhh i see it's x^{2/3}y
please put the parentheses to show that (2/3) is an exponent yes that's right

Answer 13

\[\huge\rm \frac{ x^2y^{-1} }{ x^{\frac{ 2 }{ 3 }} y^1 }\]
when you divide same bases you should `subtract` their exponents

Answer 14

\(\color{blue}{\text{Originally Posted by}}\) @ducksonquack
My answer is \[x^{4/3}\div2y\]
\(\color{blue}{\text{End of Quote}}\)
your x exponent is right x^{4/3} is correct
but it's not 2y
i assume that's a typo

Answer 15

Can you explain it to me then?