If
$z = \frac{ \left\{ \sqrt{3} \right\}^2 - 2 \left\{ \sqrt{2} \right\}^2 }{ \left\{ \sqrt{3} \right\} - 2 \left\{ \sqrt{2} \right\} }$
find $\lfloor z \rfloor$.

Question

If
$z = \frac{ \left\{ \sqrt{3} \right\}^2 - 2 \left\{ \sqrt{2} \right\}^2 }{ \left\{ \sqrt{3} \right\} - 2 \left\{ \sqrt{2} \right\} }$
find $\lfloor z \rfloor$.

ahsome · Answer

Do you mean the absolute of $z$?

zmudz · Answer

no, the floor function

zmudz · Answer

so the integer when you round the answer down

zmudz · Answer

And the answer is not 0

amilapsn · Answer

Without using a calculator, right?

zmudz · Answer

I tried with a calculator already, didn't give me the right answer.

amilapsn · Answer

What is the value that's given by the calculator?

zmudz · Answer

0.9 (and a whole bunch of numbers after that but they don't affect the rounding)

amilapsn · Answer

Then the answer should be 0

amilapsn · Answer

Hey I think you've forgotten the minus sign :-)

amilapsn · Answer

Because the answer should be a inus value.....

amilapsn · Answer

*minus

zmudz · Answer

@amilapsn nope, not -1 either :(

amilapsn · Answer

Sorry I got it wrong >_< the answer is positive..... Your answer is correct. Zero

zmudz · Answer

@amilapsn not 0 either :( i think im going to give up on this problem

amilapsn · Answer

I think you should double check that you've got that question right. Otherwise zero should be the answer...