Question

lim t->0 [1/(t√(1+t))-(1/t)]

Answer 1

\[\lim_{x \rightarrow 16} (\frac{ 1 }{ t \sqrt{1+t} } - \frac{ 1 }{ t })\]

Answer 2

(1-(17)^1/2 /(17)^1/2) 1/16

Answer 3

hint:
your function, is continue at t=16

Answer 4

*as t approaches 0... sorry

Answer 5

you have to replace t with 16 only

Answer 6

its \[-\]

Answer 7

when t---->0

Answer 8

the answer is -1/2

Answer 9

yes, the answer is -1/2 @vvvbb

Answer 10

yes... so how do I get there?

Answer 11

choose common denominator and simplify

Answer 12

then you get\[\frac{ 1-\sqrt{1+t} }{ t \sqrt{1+t}}\]