Question

Find the value x such that f(x)=0, if f(x)=(3x-4)/(5)

Answer 1

just solve (3x-4)/5=0

Answer 2

\(\bf f(x)={\color{blue}{ y}}=0\qquad {\color{blue}{ f(x)}}=\cfrac{3x-4}{5}\qquad thus
\\ \quad \\
{\color{blue}{ 0}}=\cfrac{3x-4}{5}\impliedby \textit{solve for "x"}\)

Answer 3

I already know all of that I just don't remember how to solve (3x-4)/5

Answer 4

(3x-4)/5 there is nothing to solve here

do you mean you don't remember how to solve (3x-4)/5=0?

Answer 5

the fraction is zero when the top is 0

Answer 6

that you only have to solve 3x-4=0

Answer 7

so the zero cancels out the 5?

Answer 8

(3x-4)=0 *5
3x=4
x=

Answer 9

@jewlzme17 u should try little

Answer 10

I know the answer it 4/3 its just I am having trouble understanding how. You guys are all saying different things and it's confusing. Like can someone just break it down barney style without being rude?

Answer 11

if 3x-4=0
then 3x has to be 4
another way to say this is 3x=4

Answer 12

can you solve for x now?

Answer 13

no one has said anything different

Answer 14

each of us has given you part of how to get there

Answer 15

@jdoe0001 showed you exactly what f(x)=0 meant
@dinamix showed you how to get to 3x=4

Answer 16

oh and i forgot to add what I said
@freckles said f(x)=0 when the numerator=0

Answer 17

What I'm confused on is what you do with the denominator?

Answer 18

the bottom is always 5
it has no deciding factor when the fraction is 0

Answer 19

do you know that 0/anything is 0


(when anything isn't 0)

Answer 20

\[h(x)=\frac{f(x)}{g(x)}=0 \text{ when } f(x)=0
\text{ when } x \text{ is in the domain of } h \]

Answer 21

the only that gets to decide a fraction is 0 when the top is 0 on that function's domain of course

Answer 22

OKay that makes so much more sense. Thank you

Answer 23

\[\frac{3x-4}{5}=0 \implies 3x-4=0\]

Answer 24

though you could have also decide to multiply both sides by 5
and that also works