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Physics 19 Online
OpenStudy (anonymous):

Really simple problem, so can someone help me out! I appreciate it! I had to measure the radii, circumferences, and areas of some circles. I put the data into a table and was asked to graph the radius (cm) to Circumference (cm). I did so and then it asked me to find the experimental equation. I know that the accepted is A=2pir, so what is the experimental? Thanks a lot!

OpenStudy (anonymous):

or how do I find the experimental I should say.

OpenStudy (anonymous):

@Hero @Abhisar @dakotahducharme @zepdrix @Luigi0210 @Compassionate @nincompoop @freckles @midhun.madhu1987 @adrynicoleb

OpenStudy (anonymous):

Suppose on y you graph circumference and on x you graph radius then we will get a straight line of equation \[y=mx+c\] Since this straight line passes through origin, c=0 we have \[y=mx\] \[2\pi.r=mr\] Where m is the slope using this you can find the slop as 2pi, I'm not sure if this is what they are asking

OpenStudy (anonymous):

They want an equation with another number that is similar, as I am also asked to find percent error.

OpenStudy (anonymous):

after I find the experimental equation

OpenStudy (anonymous):

Hm, I can't understand what they want, lol sorry :/

OpenStudy (anonymous):

but is there a way to calculate something like pi that can replace it?

OpenStudy (anonymous):

with the specific data I found

OpenStudy (anonymous):

Well if you divide the circumference by the diameter, you will get pi

OpenStudy (anonymous):

that's the definition of pi itself

OpenStudy (anonymous):

oh, I think I get what I need to do

OpenStudy (anonymous):

I do that to find pi and see how close it is

OpenStudy (anonymous):

with percent error

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

Awesome, thanks for the help!

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