If sin(x) = 1/3 and sec(y) = 5/4, where x and y lie between 0 and π/2, evaluate sin(x + y).
@ganeshie8 I actually have no idea what's going on here, so if you're online, I would love your help. thanks
recall the angle sum identity for sin : \[\sin(x+y)=\sin x\cos y + \cos x\sin y\]
basically you need to find those four pieces : \(\sin x, \cos x, ~~\sin y, \cos y\) then plug them in
Alright, so I'm assuming that it would look a little like this: \(\sin (x + y) = (\frac{1}{3} )(\frac{5}{4})+ \sin(y)\cos(x) \)
that's all we appear to know at this moment in time
you have the correct idea but we don't really know the value of \(\cos y\) yet, what we're given is \(\sec y\) and not \(\cos y\)
so we need to find \(\cos y\), \(\sin y\) and \(\cos x\) somehow from the given info
oh whoops, completely forgot about the secant ;-;
riiight
its easy, lets find them
Fair enough. Let's do it
do you like triangles we're gonna need bunch of them
triangles are good with me
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