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For the equation x^2+y^2-8x-2y-19=0 do the following. a. find the center (h,k) and the radius r of the circle. b. graph the circle. c. Find the intercepts, if any.
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you have to complete the square twice do you know how to do that?
Yes, I do! I just don't really know how to do that with this problem...
\[x^2-8x+y^2-2y=19\]
half of 8 is 4, half of 2 is 1 go right to \[(x-4)^2+(y-1)^2=19+4^2+1^2\] and work from there
ok! Thank you! I have to write that down
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yes you should write it down yw
I meant to write it down so i can work it out and transfer it on to my online class... :)
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