Question

A reaction has a rate law of : rate = k [ClO3-] [Cl-] [H+]2. If the initial reaction rate is 3.2E-3 M/s, then what is the rate constant if the initial concentrations are [ClO3-]o= 0.10 M, [Cl-]o= 0.10 M, [H+]o= 0.20 M ? (units are M-3 " s-1)

A) 1.6

B) 8.0

C) 1.2

D) 0.62

E) none of these

Answer 1

@Abhisar

Answer 2

Ok, so have you tried it first urself?

Answer 3

i think you would say 3.2 E-3 M/s = k [0.10] [0.10] [0.2]
k= (3.2E-3/([0.10]*[0.1)]*[0.20])

Answer 4

Yes, that's correct c:

Answer 5

k= 0.064

Answer 6

Check for one thung!!!

Answer 7

so i guess D iis closest

Answer 8

No, you did a minor mistake !!!

Answer 9

actually wrong brackets... 1.6

Answer 10

A?

Answer 11

\(\sf Rate = k[ClO_3^-][Cl^-][H^+]^2\)

Answer 12

So, K should be equal to ???

Answer 13

1.6*0.10*0.20*0.10=3.2 E-3 (the initial rate)

so k is 1.6

Answer 14

A :) thank you

Answer 15

That was incorrect :(

Answer 16

Nuuuuu!!!

\(\sf K=\Large \frac{Rate}{[ClO_3^-][Cl^-][H^+]^2}\)

Answer 17

You need to keep the order as given, I said you did a mistake. look above.. :(

Answer 18

i got 1.6 when i calclulated that

Answer 19

It should be 8

Answer 20

\(\sf K=\Large \frac{3.2 \times 10^{-3}}{0.1\times 0.1 \times (0.2)^2}\)

Answer 21

why is 0.2 squared

Answer 22

Because the Rate Law is given as
\(\sf Rate = k[ClO_3^-][Cl^-][H^+]^2\)

Answer 23

oh okay I didn't see that !

Answer 24

C;

Answer 25

thank you!