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Mathematics 19 Online
OpenStudy (mendicant_bias):

(Introductory Real Analysis) I'm trying to show that sqrt(p) is irrational if p is prime, but I have no idea where to start; could anybody give me suggestions without outright telling me what to do? e.g. should I start from a specific type of argument, contrapositive/counterexample/contradiction, etc, or should I mess around with some field axioms?

OpenStudy (anonymous):

contradiction would be your best bet i reckon? dan is the master so listen to him

OpenStudy (dan815):

i really dont know what to do yet xD

OpenStudy (dan815):

but im thinking contradiction is the easiest too

OpenStudy (mendicant_bias):

That's what I'm thinking too, messing around with it on a whiteboard. Prime numbers cannot be even, so p must be odd; both a and b must be either both odd or both even because of p being odd.

OpenStudy (mendicant_bias):

Now I'm thinking of trying to prove a contradiction from this, or something. I'll see in a minute.

OpenStudy (mendicant_bias):

A and b can't be even, because they wouldn't be in lowest terms (where a and b are the integers forming a fraction in lowest terms, equaling sqrt(p).

OpenStudy (mendicant_bias):

So a and b must both be odd. Now I'll try to contrive a contradiction from this, but IDK if this will work the same way as it does with something like sqrt(3).

OpenStudy (dan815):

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