Ask your own question, for FREE!
Physics 22 Online
OpenStudy (osanseviero):

Electric field question

OpenStudy (osanseviero):

There is an electrical field. There is a line with constant density. We know L (how long is the line). At a distance a from the middle, there is a point. Which is the field there? |dw:1441428125288:dw|

OpenStudy (unklerhaukus):

is \(L\gg a\)?

OpenStudy (osanseviero):

Yep

OpenStudy (osanseviero):

It is not infinite though, so I don't think we can use Gauss here

OpenStudy (osanseviero):

Actually it does not say anything about the relationship between a and L

OpenStudy (unklerhaukus):

i don't know how to deal with the fringing effects the occur at the the end point of the line, i do know how to get the E field if the line if infinite, (good approximation if a<<L)

OpenStudy (unklerhaukus):

hmm i maybe if a is a point above the MIDDLE of the line , the fringing effect from both sides cancel

OpenStudy (osanseviero):

It is in the middle

OpenStudy (osanseviero):

So I would guess that in horizontal all of them cancel

OpenStudy (unklerhaukus):

|dw:1441430062457:dw|

OpenStudy (osanseviero):

So I would have to use Gauss?

OpenStudy (unklerhaukus):

yeah use this cylinder as your gaussian pill box

OpenStudy (osanseviero):

Doing that I have E(2pi*a*L) = Qin / epsilon. But they told me doing this was not correct

OpenStudy (unklerhaukus):

is Qin the total charge of the line?

OpenStudy (unklerhaukus):

i think you have to express the charge in terms of a linear charge density \(\lambda\) \[\lambda = q/L\]

OpenStudy (osanseviero):

E = lambda/(2 * pi * a * Eo) (Eo is the epsilon)

OpenStudy (osanseviero):

But still...how would you solve this without Gauss?

OpenStudy (unklerhaukus):

you mean like using Coulombs law?

OpenStudy (osanseviero):

Yep. Coulomb + Electric field

OpenStudy (osanseviero):

And charge distributions

OpenStudy (osanseviero):

Found an answer, thanks a lot

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!