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Mathematics 17 Online
OpenStudy (anonymous):

.

OpenStudy (anonymous):

|dw:1441573642078:dw|

OpenStudy (anonymous):

@freckles

OpenStudy (iwillrektyou):

n this case, you need the distance formula.

OpenStudy (iwillrektyou):

Those are ordered pairs, right? That show where each point is located?

OpenStudy (anonymous):

ya

OpenStudy (iwillrektyou):

Do you know the distance formula?

OpenStudy (anonymous):

sqrt of x2-x1 ^2+ y2-y2^2 pronounced y-1, not y ^2

OpenStudy (iwillrektyou):

Yes. So in order to find the area, you have to find the distance between the length and the width seperately. First, do (-5, 3), and (7, -6).

OpenStudy (iwillrektyou):

Just substitute and solve. Let me know if you need help.

OpenStudy (anonymous):

64+169

OpenStudy (anonymous):

want me to continue or something???

OpenStudy (iwillrektyou):

Yes. I will check your answers as you go, if you would like.

OpenStudy (anonymous):

233 now what???

OpenStudy (iwillrektyou):

You have to do the same thing with the points (-2, 7) and (-5, 3)

OpenStudy (anonymous):

81+64 145

OpenStudy (iwillrektyou):

In order to find the width. Then, you just multiply the 2. I will be checking your work,

OpenStudy (anonymous):

what do i do in order to find the width??

OpenStudy (iwillrektyou):

To find the width, use the distance formula for these 2 points: (-2, 7) and (-5, 3)

OpenStudy (anonymous):

yah wchich is 145

OpenStudy (iwillrektyou):

Yes. To find the area, just multiply the length and width together.

OpenStudy (anonymous):

um that's 33785 AAAANNNNDDD thats not an answer choice you are wrong

OpenStudy (iwillrektyou):

I am checking your work, and a step was done wrong.

OpenStudy (iwillrektyou):

For the width, it is 5.

OpenStudy (iwillrektyou):

And I am double checking my work for the length,

OpenStudy (anonymous):

how do you get 5??????

OpenStudy (iwillrektyou):

Ok so, Sqrt (-5 + 2)^2 + (3 - 7)^2 --> Sqrt (-3)^2 + (-4)^2 --> Sqrt (9 + 16) --> 5

OpenStudy (anonymous):

okay okaywhats the lenght

OpenStudy (iwillrektyou):

15

OpenStudy (iwillrektyou):

But do you understand the concept?

OpenStudy (freckles):

"Yes. So in order to find the area, you have to find the distance between the length and the width seperately. First, do (-5, 3), and (7, -6). " \[\text{ distance between these two points is } \\ \sqrt{(-5-7)^2+(3-(-6))^2} \\ =\sqrt{(-5-7)^2+(3+6)^2} \\ =\sqrt{(-12)^2+(9)^2} .. \text{ so on ... }\]

OpenStudy (anonymous):

yeah so 75

OpenStudy (iwillrektyou):

Yes. 75 is correct.

OpenStudy (anonymous):

can you help with one more?

OpenStudy (iwillrektyou):

I will try, but I am not very good at geometry, as I just started learning it. But shoot.

OpenStudy (anonymous):

|dw:1441574726192:dw| find the perimeter

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