Let f(x)= sqrt of x and g(x)=cubed root of 1-x. Find a formula for g(f(x) and find it's domain

Question

danjs · Answer

$$g(f(x))=\sqrt[3]{1-f(x)} = \sqrt[.3]{1-\sqrt{x}}$$

dinamix · Answer

$$\sqrt[3]{1-\sqrt{x}}$$@Blairortiz

dinamix · Answer

lol  @DanJS

danjs · Answer

hit post at the same time

dinamix · Answer

yeah

danjs · Answer

@Blairortiz 

Do you know the domain of the square root and the cubed root functions?

anonymous · Answer

No

dinamix · Answer

$$x ^{1/2} =\sqrt{x}$$

dinamix · Answer

$$\sqrt[3]{x}=x ^{3/2}$$

anonymous · Answer

So the domain is x^3/2 and x^1/2?

danjs · Answer

$$\sqrt x$$
For this x has to be greater than or equal to zero, so the domain of f(x) is all x greater than or equal to zero...

danjs · Answer

The cubed root function can have any real number as a value of x...

danjs · Answer

attachment

danjs · Answer

So for the g(f(x)),   the domain is all x greater than or equal to zero, the red function in the graph