Question

Let f(x)= sqrt of x and g(x)=cubed root of 1-x. Find a formula for g(f(x) and find it's domain

Answer 1

\[g(f(x))=\sqrt[3]{1-f(x)} = \sqrt[.3]{1-\sqrt{x}}\]

Answer 2

\[\sqrt[3]{1-\sqrt{x}}\]@Blairortiz

Answer 3

lol @DanJS

Answer 4

hit post at the same time

Answer 5

yeah

Answer 6

@Blairortiz

Do you know the domain of the square root and the cubed root functions?

Answer 7

No

Answer 8

\[x ^{1/2} =\sqrt{x}\]

Answer 9

\[\sqrt[3]{x}=x ^{3/2}\]

Answer 10

So the domain is x^3/2 and x^1/2?

Answer 11

\[\sqrt x\]
For this x has to be greater than or equal to zero, so the domain of f(x) is all x greater than or equal to zero...

Answer 12

The cubed root function can have any real number as a value of x...

Answer 13

So for the g(f(x)), the domain is all x greater than or equal to zero, the red function in the graph