Question

mean question

Answer 1

using your data, we can write this:
\[\Large \frac{{{x_1} + {x_2} + {x_3} + {x_4} + {x_5}}}{5} = 14\]
where \( \large x_1,x_2,x_3,x_4,x_5\) are the requested positive numbers
Now, if we choose \( \large x_3= 10 \), then we have:
\[\Large {x_1},{x_2} < 10,\quad {x_4},{x_5} > 10\]
by definition of median

Answer 2

I see, but how would you simplify that

Answer 3

we can write this:
\[\Large \begin{gathered}
{x_1} + {x_2} + 10 + {x_4} + {x_5} = 70 \hfill \\
\hfill \\
\left( {{x_1} + {x_2}} \right) + \left( {{x_4} + {x_5}} \right) = 60 \hfill \\
\end{gathered} \]
now I can choose \( \large x_1=5,x_2=9 \)
so, what is \( \large x_3+x_4 =...?\)

Answer 4

I dont know

Answer 5

I would tihnk that you couldnt combine

Answer 6

if I substitute, I get this:
\[\Large {x_4} + {x_5} = 60 - 9 - 5 = 46\]

Answer 7

so I can choose these values:
\[\Large {x_4} = 22,\quad {x_5} = 24\]

Answer 8

so is that what you would put to answer the first question?

Answer 9

yes!

Answer 10

here are the five positive numbers:
\[\Large {x_1} = 5,\quad {x_2} = 9,\quad {x_3} = 10,\quad {x_4} = 22,\quad {x_5} = 24\]

Answer 11

ok so i put those and thats it?

Answer 12

yes!

Answer 13

alright cool

Answer 14

what about what processi used

Answer 15

I have used the definition of \( \large median \) and the definition of \( \large mean \) of a distribution of data

Answer 16

I see well ok that makes snese