Question

Find x in this proportion.

x|3 = x+2|5

(they are fractions. Please show answer and how you got it!)

Answer 1

@Nnesha
@e.mccormick
@Donblue

Answer 2

So x is to 3 as x+2 is to 5? Know how to set those up in fractional form?

Answer 3

\(\frac{x}{3}=x+\frac{2}{5}\)

I think the easiest thing would be to multiply everything by the LCM of the denominators, which is 15

\(15\frac{x}{3}=15x+15\frac{2}{5}\)

\(5x=15x+6\)

Can you solve now?

Answer 4

zz, I think they meant:
\(\dfrac{x}{3} = \dfrac{x+2}{5}\)

Answer 5

Was it \(\frac{x}{3}=\frac{x+2}{5}\)?

Answer 6

x/3=x+ 2/5
or , 5x=15x+6
or, 15x+6=5x
or,10x=6
or,x=6/10=3/5=0.6

Answer 7

ye @e.mccormick
and @Learner11 i tried that, thats wrong

Answer 8

ahh, try the same thing with that!


\[\frac{x}{3}=\frac{x+2}{5}\]


\[15*\frac{x}{3}=15*\frac{x+2}{5}\]

\[5x=3(x+2)\]

now solve for \(x\)?

Answer 9

answer choices are -1 , 1 , 2, 3.
:P i keep doin this wrong

Answer 10

As a general rule:

\(\dfrac{a}{b}=\dfrac{c}{d}\) type proportions can alsways use cross multiplication to move forward. Cross multiplication basically does what xx did. He just multiplied hte bottoms (3 and 5) first. But if you don't multiply them out, then you can cancel quickly:

\(\dfrac{a}{b}=\dfrac{c}{d}\)

\(\dfrac{a}{b}\times \dfrac{bd}{1}=\dfrac{c}{d}\times \dfrac{bd}{1}\)

\(\dfrac{a}{\cancel{b}}\times \dfrac{\cancel{b}d}{1}=\dfrac{c}{\cancel{d}}\times \dfrac{b\cancel{d}}{1}\)

\(\dfrac{a}{1}\times \dfrac{d}{1}=\dfrac{c}{1}\times \dfrac{b}{1}\)

\(a\times d=c\times b\)

\(ad=cb\)

That is a general way to start. Then solve for the unknown...

Answer 11

thank you!

Answer 12

What steps are you using when you solve the:

5x=3(x+2)