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(X-2)^1/2=5 Solve
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you can convert 1/2 exponent to square root \[\huge\rm [x^\frac{ 1 }{ 2 }=\sqrt{x}\]
ignore `[`
so (x-2)^1/2 is same as \[\sqrt{x-2} =5\] take square both sides to cancel out the square root
\[\huge\rm (x-2)^\frac{ 1 }{ 2 }=5\] or keep the 1/2 exponent same thing now take square both sides \[\huge\rm ((x-2)^\frac{ 1 }{ 2 })^2=(5)^2\]
any question :? understand or not ? let me know what you get after that
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Oh ok now I see I got it. What about if the exponent us 1/3
remember the exponent rule \[\huge\rm x^\frac{ m }{ n }=\sqrt[n]{x^m}\] denominator of the fraction would represent index
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