Question

A 2.0 L vessel contains HI and H2. The following equilibrium is established:

H2 (g) + I2 (g) ⇌ 2 HI (g)

At equilibrium

[H2] = 2.0 M
[I2] = 1.5 M
[HI] = 2.5 M

The initial concentration of I2 was not mentioned so you must assume [I2]o = 0.

Calculate the initial moles of:



HI
(Tol: ± 0.1)
H2 (g)
(Tol: ± 0.1)

Answer 1

@Abhisar @Photon336

Answer 2

You could work backwards

Answer 3

wait those +/- thats the change in concentration right? @Lena772