OpenStudy (anonymous):

Please help me : find the limit lim (10/ln|x|) as x approaches to +infinity and then as x approaches to - infinity

2 years ago
hartnn (hartnn):

just plug in whats \(\ln(\infty )\)

2 years ago
OpenStudy (anonymous):

lim

2 years ago
OpenStudy (anonymous):

lim 10/ln|x|

2 years ago
hartnn (hartnn):

yeah, thats the question, when you plug in the value of x. you get 10/ln |infinity| you can find that value if you know whats ln |infinity| = ...

2 years ago
OpenStudy (anonymous):

... and whats the limit of ln|infinity| ?

2 years ago
hartnn (hartnn):

let me ask this way, infinity represents a very large number so logarithm of a very large number is : (A) very large number or (B) very small number ?

2 years ago
OpenStudy (anonymous):

a ?

2 years ago
hartnn (hartnn):

yes so ln |infinity| = infinity! and whats 10/infinity??

2 years ago
OpenStudy (anonymous):

the answer must be 0 ! i got the key answers

2 years ago
OpenStudy (anonymous):

it's the absolute value what really confuses me

2 years ago
hartnn (hartnn):

yes, 10 divided by a very large number = very small number = 0

2 years ago
OpenStudy (anonymous):

ok , then whats the difference between lim ln(infinity) and lim ln|infinity| ?

2 years ago
hartnn (hartnn):

|a| = a when a >= 0 and |a| = -a when a<0 example : |4| = 4, because 4 is >0 |-5| = -(-5) = 5 because -5 is <0 same goes for |infinity|

2 years ago
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