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Mathematics 29 Online
OpenStudy (anonymous):

Find the limit of the function by using direct substitution. limit as x approaches zero of (x^2 + 5)

OpenStudy (alekos):

just substitute x = 0 and you have the limit as x -> 0

OpenStudy (anonymous):

so 5?

OpenStudy (alekos):

yep

OpenStudy (anonymous):

can you help me with one more?

OpenStudy (alekos):

fire away

OpenStudy (anonymous):

Find the limit of the function algebraically. limit as x approaches four of quantity x squared minus sixteen divided by quantity x minus four.

OpenStudy (anonymous):

I think it's 8 but I'm not sure

OpenStudy (welshfella):

note if you plug in x = 4 you get 0/0

OpenStudy (anonymous):

so no limit?

OpenStudy (welshfella):

oh you can divide of course Silly me dividing gives x + 4

OpenStudy (anonymous):

so it is 8?

OpenStudy (anonymous):

@welshfella

OpenStudy (welshfella):

yes i would say so limits are not my strong point though just a sec

OpenStudy (anonymous):

okay

OpenStudy (welshfella):

yes 8 it is

OpenStudy (welshfella):

limit as x approaches 4 of (x^2 - 16)/ (x - 4)

OpenStudy (anonymous):

Yay! thank you

OpenStudy (welshfella):

the above link confirms it

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