Question

Plz help with these questions to see if im right

Answer 1

we have to determine if the equation has real or imaginary solutions by solving

Answer 2

@jim_thompson5910 @surjithayer

Answer 3

show what you have so far

Answer 4

Well i only have the first one and i said it was a real soultions

Answer 5

yes that first one definitely has 2 real solutions. Were you able to find the actual solutions?

Answer 6

with the 3rd equation start by subtracting 9 to get (x^2=-6)

Answer 7

yea well i didi have it written down

Answer 8

ok show us your work please

Answer 9

the soluion would come out to a decimal if you work the rest out thats your hint for question 3

Answer 10

x= ± 2 21−−√ 7
x≈1.30930734,−1.30930734

Answer 11

thats all i havee for number 1

Answer 12

for number two i have this hold on

Answer 13

x=±i6√

Answer 14

i say spot one because of the simplification it checks out

Answer 15

so i think number two is imaginary soutions bevause of the i in the answer

Answer 16

#2 does have imaginary (aka non real) solutions

but it's not x=±i6√

Answer 17

What is it

Answer 18

then again i am shorting out from the day i had at school with 3 tests so im good for a few helpings tonight

Answer 19

after you distributed, what did you get?

Answer 20

i just put it in a math solver

Answer 21

0 doennt equal -3

Answer 22

oh, so you're working on #3 then

Answer 23

nope still 2nd

Answer 24

im worked out the second one and got 0=-3 and thats not possible

Answer 25

i'm referring to this one as the second (since you posted it second)

http://assets.openstudy.com/updates/attachments/56020960e4b0ad22e8a696f9-geekfromthefutur-1442974199899-win_20150922_220854.jpg

Answer 26

Ohhh sorry my bad yea we are working on the 3rd one my bad

Answer 27

square root 6

Answer 28

How would i write this in two little lines catman

Answer 29

sorry my pc just crashed but it restarts fast

Answer 30

ok

Answer 31

you round the decimal to the nearest hundreth

Answer 32

so it would be 2.45 instead of 2.449

Answer 33

ok

Answer 34

Wait what decimal

Answer 35

the square root of 6

Answer 36

is not a whole number

Answer 37

2.44948974278

Answer 38

but instead it would be 2.45 as you round the 9 to the 2.44 to a 2.45. note you cannot round up a if the number behind it is less than five for example if the number was 32 it cannot be rounded to 40 it would round down to 30

Answer 39

ok and what about the next problem

Answer 40

you mean #3?

Answer 41

yea

Answer 42

if you subtract 9 from both sides, you'd get x^2 = -6

taking the square root of both sides leads to what your solver got

Answer 43

ok x=i,−i

Answer 44

so imaginary

Answer 45

no it should be \[\Large x = \pm i*\sqrt{6}\]

Answer 46

oh ok

Answer 47

Real quick @jim_thompson5910 this went for this one?

Answer 48

oh, I see now

yes, the solution to that one is definitely x = i or x = -i

Answer 49

So what we went over was for this one

Answer 50

but the one you said it should be that was for the middle one

Answer 51

yeah the solution to #2 is x = i or x = -i