Question

Vector A⃗ has a magnitude of 3.00 and is directed parallel to the negative y-axis and vector B⃗ has a magnitude of 3.00 and is directed parallel to the positive y-axis. Determine the magnitude and direction angle (as measured counterclockwise from the positive x-axis) of vector C⃗ , if C⃗ =A⃗ −B⃗ .

Answer 1

Now, \(\sf |\vec{C}|=|\vec{A}- \vec{B}| = \sqrt{A^2+B^2-2ABCos180}\)

Answer 2

Angle will be 45 degrees from the +x axis in clockwise sense.