Question

Am I right? check below:

Answer 1

@freckles @Jhannybean I just wanted to know if my domain for the inverse is right or not...

Answer 2

Its kind of messy XD

Answer 3

your answer is correct

Answer 4

both parts

Answer 5

okay thank you. I learned something from you yesterday :)

Answer 6

Instead of writing it as \(y=\dfrac{\ln\left(\dfrac{x+1}{3}\right)-1}{2}\), I would write \(y= \dfrac{\ln(x+1)-\ln(3)-1}{2}\)

Answer 7

Otherwise it looks great!

Answer 8

thank you so much for all your help :)