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Linear Algebra
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[-4 -1 5] A=[-3 1 9] [3 -3 -15] Observe that the third column of A is -2 times the first column plus 3 times the second column. Use this information to find a nontrivial solution to Ax = 0
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I don't know how the logic on it. I solve it as usual and get the result (2, -3,1). Then I tried to link to what they hint. \(Column_3 = -2~Column_1+3~Column_2\), hence \(C_3 + 2C_1-3C_2=0\) Reorder it , we have \(2C_1- 3C_2 +C_3=0\) and observe that the coefficient of them is our solution \(\left[\begin{matrix}2\\-3\\1\end{matrix}\right]\)
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