Electron Configuration question: How do you write the electron configuration if an Element has a charge? Example: V^5+ I heard that p and s blocks get taken off respectively before the d block. But how would it look like?
you remove electrons that are higher in energy (e.g. 4s electrons before 3d electrons) so for vanadium, you have \(\sf [Ar]3d^34s^2\) you remove the 2 4s elctrons and the 3 3d electrons, leaving with you just the electronic configuration of Ar.
Thanks. So you remove s electrons and d next? What about the p electrons?
the 3p electrons would be next, but it's not really common for vanadium to lose some many electrons because it would take too much energy.
Okay. I think I got it. Thanks!
No problem. If you have another example you can post what you think the answer is and i can check it.
Will do :)
Let's say it's Ni2+ would the electron config be [Ar]3d^8 ?
yes
\(\huge \checkmark\)
Yeeey. Thanks a lot. I think i got it now :)
sweeet, no problemssss
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