Question

If a ball dropped from a tower reaches the ground after 3.5 seconds, what is the height of the tower?
Given: g = -9.8 meters/second2
a.) 56 meters
b.)60.03 meters
c.)62.08 meters
d.)62.50 meters

Answer 1

it is b

Answer 2

\[d=v_0t+\frac{ 1 }{ 2 }at^2\]

Answer 3

\[s=\frac{1}{2}g t^2\]
Your answer will come in negative of course due to negative value of g that is taken, it simply means that the displacement is in the same direction as the acceleration, it's magnitude you can take as
\[|s|=\frac{1}{2}t^2|g|\]