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OpenStudy (anonymous):
explain plz.
OpenStudy (alexandervonhumboldt2):
ok so first count the slope on the grath: chose points (-2, 0) (0, 2)
OpenStudy (anonymous):
uh hu and then..
OpenStudy (alexandervonhumboldt2):
use slope formula (y1-y2)/(x1-x2)=(0-2)/(-2-0)=-2/-2=1
OpenStudy (anonymous):
?
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OpenStudy (alexandervonhumboldt2):
so the slope is 1
OpenStudy (anonymous):
ok i still don't get it
OpenStudy (alexandervonhumboldt2):
the grath is 2 units upper than the 0, 0 point.
thus b in the equation y=x+b is 2
thus the equation is t=x+2
OpenStudy (alexandervonhumboldt2):
woops i meant y=x+2
OpenStudy (anonymous):
i see thxs!
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OpenStudy (anonymous):
can you stay to help me on other questions!
OpenStudy (anonymous):
so who is correct?
OpenStudy (anonymous):
If x can be any number, how many solutions are there for the equation?
y = 4x – 1
A.
There are two solutions.
B.
There is no solution.
C.
There are many solutions.
D.
There is only one solution.
OpenStudy (anonymous):
@texaschic101
OpenStudy (texaschic101):
I was wrong on the first one...I miscalculated...sorry.
If x can be any number, and the equation still be true, then there is infinite solutions
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OpenStudy (anonymous):
oh ok its ok.
OpenStudy (anonymous):
can u solve second please @texaschic101
OpenStudy (texaschic101):
already did....if x can be any number, and the equation still be true, then there is infinite solutions
OpenStudy (anonymous):
thxs!
OpenStudy (texaschic101):
glad to help :)
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OpenStudy (anonymous):
The vertices of a right triangle are (0, 5), (5, 0), and (5, y).
What is the value of y?
( , )
OpenStudy (anonymous):
@texaschic101
OpenStudy (texaschic101):
I am thinking (5,5)...but you might want to get a second opinion
OpenStudy (anonymous):
ok I was thinking same but wasnt sure so yeah @texaschic101
OpenStudy (anonymous):
@AlexandervonHumboldt2 please solve second question