Question

The perimeter of a rectangle is 64 units. Can the length x of the rectangle can be 20 units when its width y is 11 units?

Answer 1

please help me guys!

Answer 2

well think what is the formula to find the perimeter?

Answer 3

a+b+c?

Answer 4

?????

Answer 5

P=2(l+w)

Answer 6

i dont remember

Answer 7

so now do the math with the formula

Answer 8

can you give me the answer then we discuss it?

Answer 9

perimeter of rectangle is : P = 2L + 2W

start subbing in :
P = 64
L = 20
W = 11

if it comes out correct, then it can be a solution
if it comes out incorrect, then it cannot

Answer 10

here are my options

Answer 11

No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 64
No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32
Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 64
Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 32

Answer 12

20+11*2=62

Answer 13

no option has 62 as an answer

Answer 14

ok...lets sub

P = 2L + 2W
64 = 2(20) + 2(11)
64 = 40 + 22
64 = 62....it cannot be true

Answer 15

the= with a line through it means not = to. get it?

Answer 16

yeah

Answer 17

so whats the final answer from the options?

Answer 18

I would say A

Answer 19

ok thx!!!!

Answer 20

no problem do you need more help?

Answer 21

It doesn't make much sense....x and y do not have to equal 64.....2x + 2y have to equal 64

Answer 22

so whats the answer? texaschic

Answer 23

yes buttons i could use some more help.

Answer 24

k what do ya need

Answer 25

I think it is B