Question

Solve using any appropriate method

Answer 1

\[A=\frac{ 1 }{ 3}\]

\[B=-\frac{ 1 }{ 3}\]

Answer 2

one method (elimination)
multiply the second equation by -5 then add to the first. this gives one equation with one unknown. solve for b then substitute to get a

Answer 3

triciaal i've been trying to do elimination but I just never get it right

Answer 4

My answer is right

Answer 5

Thank you Austin :) you where right last time as well,I wish I could help you with your math but it looks scary lol

Answer 6

Yours is easier then mine

Answer 7

D:

Answer 8

another method (substitution)
the second equation can be factored 3 is common. using the expression for a substitute in equation 1 and solve for b. use this value of b in the expression for a to get the value.

Answer 9

I know lol Its just a hybrid class and I just got introduced this on friday as in I havent had a lecture for this yet till tomorrow -___- but the hw is due today

Answer 10

Need more help unicorn?

Answer 11

I have one problem left after this one Im just going to try triciaals method first thank you :)

Answer 12

so you want help from triciaal.

Answer 13

mmmmm k

Answer 14

@Austin1617 it's ok to help

Answer 15

I appreciate yours Austin!! But I want to try to figure this out as well. :) thanks a lott seriously

Answer 16

I have a fraction now kill me.

Answer 17

there are at least 4 ways to solve simultaneous equations.
the objective for the elimination method is to get rid of one variable. solve the linear equation then substitute to find the other value.
to get rid of the variable you choose to eliminate the coefficients must be equal and opposite.

Answer 18

fractions are just pieces-- put them together

Answer 19

I dont get it -_______-

Answer 20

where is the problem?
to get rid of the fraction, multiply each term by the lowest common denominator. (LCD)

Answer 21

I know thats what ive been doing even using a calculator to double check and I end up with decimals and stuff im just over it -__-

Answer 22

Tomorrow in lecture hopefully I get it,like i said we havent discussed it its a hybrid class so all questions are asked there

Answer 23

use the natural calculator--no extra points

Answer 24

I got every method down except elimination . substitution is ok

Answer 25

that's the one I use most often. I usually use substitution when the coefficient of one variable is 1.

Answer 26

yeah its easier.

Answer 27

there is matrix and of course graphing

Answer 28

pay attention in class and practice the problems. with practice you will "see" which method is faster for a given problem. Have fun.