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can you write an indirect proof proving only one angel of an obtuse triangle is greater than 90 degree?
90 degree is a right angle so put that as a triangle
Indirect proof is a proof of contradiction. List the things you know abot an obtuse triangle - It's a triangle so must have interior angles that total 180º a+b+c=180º - An obtuse must have one angle that is larger than 90º and less than 180º 90º<a<180º or 90º<b<180º or 90º<c<180º Now you assume that at least 2 angles of the triangle have angles greater than 90º Can you write an equation or expression for that part?
it's 90º<a<180º and 90º<b<180º - the inequalities open to the right to make it say "90 degrees is less than a, a is less than 180 degrees," but I knew what you meant. The AND was the important part) So if a AND b are both greater than 90º, what happens to c when we try to sum up the angles (a+b)+c=180
c has to be less than 90 degree?
You start with the things that must be true for every triangle a b c Reply Using Drawing For every triangle a+b+c=!180º For every obtuse triangle 90º<a<180º Assumption: both a and b are greater than 90º 90º<a<180º ; 90º<b<180º If true 180º<a+b<360º Then for (a+b)+c=!180º c<0 This makes no physical sense. Thus only 90º<a<180º can be true. There exists only one obtuse angle in an obtuse triangle. QED. the equals sign means "must be equal to." You could also use the triple equals sign
i'm sorry i confused. okay so i have to start by assuming the opposite so , at least 1 or more equals to 90 degrees right?
right
Assume the contrary: A triangle exists that has two obtuse angles. The measure of an obtuse angle is > 90 degrees The sum of the angles of this triangle will therefore be m Angle A + m Angle B + m Angle C > 180 degrees The sum of the angles of a triangle = 180 degrees CONTRADICTION Therefore, a triangle in the cartesian plane has at most one obtuse angle. (Note - a triangle can have more than one obtuse angle in non-cartesian geometries. Think about a triangle on the globe....)
Assume the contrary: A triangle exists that has two obtuse angles. The measure of an obtuse angle is > 90 degrees The sum of the angles of this triangle will therefore be m Angle A + m Angle B + m Angle C > 180 degrees The sum of the angles of a triangle = 180 degrees CONTRADICTION Therefore, a triangle in the cartesian plane has at most one obtuse angle. (Note - a triangle can have more than one obtuse angle in non-cartesian geometries. Think about a triangle on the globe....)
so i can just just put this The measure of an obtuse angle is > 90 degrees The sum of the angles of this triangle will therefore be m Angle A + m Angle B + m Angle C > 180 degrees The sum of the angles of a triangle = 180 degrees
yes
alright thank you so much
np
@Tal_Tal
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