1. Calculate the number of milliliters of 0.150 M copper(II) sulfate solution that must be diluted to prepare 10.0 mL of a 0.0750 M copper(II) sulfate solution. 2. Calculate the number of milliliters of 0.150 M copper(II) sulfate solution that must be diluted to prepare 10.0 mL of a 0.0230 M copper(II) sulfate solution.
Use M1V1=M2V2 for both questions. You're given M1, M2, and V2 in both cases, so use that information to solve for V1!
Yes, but I am confused on the units. The M for molar mass is throwing me off. How do I get the answer in milliliters?
The question is asking how many ml of M1 is needed to form 10.0 ml of M2 so in both your units are ml
The M is for molarity, not for molar mass. Molarity is a measure of moles/liter of volume (mol/L). Here you can use the volumes given in mL. No need to convert to L or anything else because you'd just end up multiplying both sides by the same factor.
okay I will work it and ask if it is correct. Thank you
1. 5 mL 2. 1.533 mL
Your 2nd answer is correct. Your 1st is incorrect. What did you enter into your calculator?
10.0 x 0.075 ________________________ .15 =5
You are correct it is 5 ml. I mistakenly read your answer as 1.5. My bad
Thank you so much!!!
Join our real-time social learning platform and learn together with your friends!