Question

Write the equation of a line that is perpendicular to the given line and that passes through the given point.

2x + 9y = –30; (–8, 0)

y = 2/9x + 36
y = 9/2x + 36
y = -9/2x + 36
y = 2/9x – 8

Answer 1

@sebaxtiangb

Answer 2

@MathleticMagicain

Answer 3

@ShadowLegendX:

Answer 4

Do you know how to start this?

Answer 5

nope

Answer 6

Write the equation of a line that is perpendicular to the given line and that passes through the given point.

2x + 9y = –30; (–8, 0)

First youʻre going to have to solve for the line 2x + 9y - 30

to get the correct slope.

Then find the line that is perpendicular to that slope

reverse, negative it

Then, we will use point slope form to input in those points, and our perpendicular line, to find our answer

Answer 7

I have to go soon, so I will try to get this displayed asap

Answer 8

confused

Answer 9

I also have a few more

Answer 10

First we simplify 2x + 9y = - 30

Basically, we want to get 2x + 9y = - 30 into a y = mx + b format

with m standing for slope and b standing for the y intercept(the point in which the line crosses the y axis)

2x + 9y = - 30

Subtract 2x from both sides

9y = -2x - 30

Divide the entire equation by 9

y = -2/9x - 30/9

Answer 11

Now we have our slope, -2/9x

We reverse it to -9/2x and then change the sign to positive

9/2x

Answer 12

D?

Answer 13

From there we go to point slope form

y - y1 = m(x - x1)

(–8, 0)

-8 is the x
0 is the y

y - 0 = m(x --8)

y - 0 = m(x + 8)

Input in our new slope

y - 0 = 9/2(x + 8)

Now we simplify

First get rid of that 0, and then distribute

y = 9/2x + 36

That is our answer

Answer 14

5.5 units right

y = | x | – 5.5
y = | x – 5.5 |
y = | x + 5.5 |
y = | x | + 5.5

Answer 15

I gtg, Iʻll be back on in a couple hours, I have to endure the traffic on the way back home :P

Answer 16

What time will you be on tomorrow?

Answer 17

mhm, I have school, so...like 10, 11hrs from now? When Iʻm free after school, I gtg now, bye

Answer 18

ok. tomorrow night at this time?