Question

Find the solutions of sin5x + sin3x = 0 in the interval [0, 2pi).

Answer 1

I got to 2sin4x cosx = 0 and got the solutions 0, pi, pi/2, and 3pi/2. I feel like some solutions are missing...

Answer 2

What did you do to obtain that answer set?

Answer 3

2sin4x = 0
cosx = 0

2sin4x = 0 equals sin4x = 0

Answer 4

@tkhunny

Answer 5

?? Where did you get sin(4x)?

Answer 6

Divided the 2 from both sides...not sure if it would work

Answer 7

Try this:

\(\sin(5x) = \sin(4x + x) = \sin(4x)\cos(x) + \cos(4x)\sin(x)\)

You do this one:

\(\sin(3x) = \sin(4x - x) = \)