Question

If csc alpha = 7/3 and cot alpha= 2 square root of 10 over 3 find sec alpha

Answer 1

HI!!

Answer 2

think of cosecant as "hypotenuse over adjacent" and draw a triangle

Answer 3

find the missing side via pythagoras
then you can take any trig ratio you like

Answer 4

After I find the missing side do I multiply them and use the keep change flip method?

Answer 5

not sure what you are asking

Answer 6

other side is \[\sqrt{7^2-3^2}=\sqrt{49-9}=\sqrt{40}=2\sqrt{10}\]

Answer 7

For the missing side it was square root of 40

Answer 8

yeah \(\sqrt{40}\) or \(2\sqrt{10}\)

Answer 9

oh wow i made a huge mistake

Answer 10

What happens after that how do I find sin if both cot and csc is 2 square root of 10

Answer 11

cosecant is the reciprocal of sine not cosine

Answer 12

Yea

Answer 13

secant is the reciprocal of cosine, so it is hypotenuse over adjacent i.e. \[\frac{7}{2\sqrt{10}}\]

Answer 14

So we multiply square root of ten on both top and bottom to cancel the square root and it gives me the final answer of 7 square root 10 over 20 thank u so much!!!!