Question

What is 64-z^6 factored down to?

Answer 1

Is this correct? Help me verify this. ---> (2-z) (z^2+2z+4 2+z) (z^2-2z+4)

Answer 2

Ops I forgot to add a ()

Answer 3

\[2^{6} - z ^{6}\]

Answer 4

a^6 - b^6 = (a + b)(a^2 - ab + b^2)(a - b)(a^2 + ab + b^2)

Answer 5

plug that into there and done

Answer 6

You got it?

Answer 7

Yeah I guess that's another way to solve it

Answer 8

That would be simplifying it fully

Answer 9

kk