Question

a spinner has 12 equal-size sector labeled 1 through 12.The spinner is spun once. what is the probability that it will land on a # greater than 3? express ur answer in as a decimal to the nearest hundreth

Answer 1

Okay, we can write out what we have. :-) Or, set up inequalities to help us, right?

Answer 2

We have numbers 1-12.
n<3 = 1, 2
n>3=4, 5, 6, 7, 8, 9, 10, 11, 12.

Answer 3

k

Answer 4

Now that we have all that set up, we can set up a fraction to help us find our probability.

Answer 5

What set of numbers do you think we will use?

Answer 6

n<3 or n>3?

Answer 7

n>3?

Answer 8

Excellent! Because it is wanting to know the probability of the spinner landing on a number that is greater than 3, which is n>3 :-)

Answer 9

ok im starting to get it but then wat?

Answer 10

n>3 = 4, 5, 6, 7, 8, 9, 10, 11, 12
9/12. Since we have 9 numbers greater than 3.

Answer 11

That should simply down to 3/4.

Answer 12

That equals 0.75.

Answer 13

so the answer is 0.75?

Answer 14

From my calculations, yes.

Answer 15

It just says n>3, right? Now \[n \ge 3?\]

Answer 16

Not*

Answer 17

thank u so much!!!

Answer 18

You're welcome. :-]