Question

Pic below

Answer 1

Where?

Answer 2

You know how to do this!!!

Answer 3

I do know how its just i have a really hard time with math....

Answer 4

@seascorpion1

Answer 5

1/x=x^-1 so in your case: x=3^5 *4^-2

Answer 6

ok so in fraction for it would be?

Answer 7

No, in your case the numerator is 4^-3*4^2*3^4.

Answer 8

i dont get it... Im sorry

Answer 9

Let me give a shot in explaining,

your problem can be divided into 2 independent problems, one with base as 3 and one with base as 4,
\(\Large \dfrac{4^{-3}4^2 }{4^{-2}}\)

\(\Large \dfrac{3^4}{3^5}\)

one of the rules you'll be using is
\(\Large x^{-n} = \dfrac{1}{x^n}\)
do you know about it already? used it before?

Answer 10

I have not used that before what is \[^{-n}\]

Answer 11

the x thing

Answer 12

also use that: \[\frac{a^m}{a^n}=a^{m-n}\]

Answer 13

Hope your ok with this, I'll check back in an hour.