OpenStudy (lanhikari22):

How would you visualize the operation and conversion of partial fractions and more compounded fractions?

2 years ago
OpenStudy (lanhikari22):

Ex: \[\frac{ 1 }{ (x+1)(x+2)(x+9) } = \frac{ A }{ x+1 } + \frac{ B }{ x+2 } + \frac{ C }{ x+9 }\]

2 years ago
OpenStudy (anonymous):

you mean how u solve it right?

2 years ago
OpenStudy (lanhikari22):

No. How to visualize it. How these changes occur, or what they could mean in the applicational world. Scaling A,B,C makes the function to the left match the one to the right. I just wonder what these characteristics are.

2 years ago
OpenStudy (lanhikari22):

@ArifL

2 years ago
zepdrix (zepdrix):

I never really got a good grasp on the justification for partial fraction decomp myself. This answer is kind of neat though, http://math.stackexchange.com/questions/20963/integration-by-partial-fractions-how-and-why-does-it-work

2 years ago
OpenStudy (lanhikari22):

@zepdrix that's a neat structure of computations, indeed. It did not discuss any theoretical insight, but it offered some ideas... such as the covering term technique. I do like to imagine this as breaking a huge, "complicated" window into smaller and simpler blocks. I just need to be able to see this in the numbers themselves and find a good analogy to confirm. But thank you. The question remains as to how to interpret them, though, or what analogy would be useful to describe this very process.

2 years ago
OpenStudy (amistre64):

the justification is; how would you add rational functions (glorified fractions) together to start with?

2 years ago
OpenStudy (lanhikari22):

@amistre64 By looking at each individual piece/ fraction and scaling them up to a common "whole piece" or picture. That's true. But how exactly does it work backwards? Breaking down your "whole picture" or denominator into smaller pieces in which the part (or the numerator) decomposes too. A

2 years ago
OpenStudy (alekos):

Partial fraction decomposition is used so we can integrate an otherwise very awkward function or also used to find the inverse Laplace transform

2 years ago
OpenStudy (amistre64):

\[\frac56=\frac A2+\frac B3\] \[6(\frac56=\frac A2+\frac B3)\] \[5=3A+2B\]

2 years ago
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