Given Right triangle ABC (right angle at C ) and DE perpendicular to AB at E. Prove triangle ABC is similar to triangle DBE. Use isometry.
Please, help

Question

Given Right triangle ABC (right angle at C ) and DE perpendicular to AB at E. Prove triangle ABC is similar to triangle DBE. Use isometry.
Please, help

loser66 · Answer

|dw:1446863249304:dw|

superdavesuper · Answer

AAA to prove similar triangles so it is right there :)

loser66 · Answer

I have to use isometry, I cannot use congruence or similarity.

loser66 · Answer

That is I have to find out a rotation or dilation or both to make the graph look similar

superdavesuper · Answer

isometry as in the ratios of the 3 sides are the same right? i think that is how to prove similar triangles w isometry...

superdavesuper · Answer

oh nvd....hmmm.....

loser66 · Answer

Like this, if I "cut" triangle BDE out and "stand" the triangle ABC up, I have:  |dw:1446870093138:dw|

superdavesuper · Answer

|dw:1446870164799:dw|

will this work? dilate BD'E' from there...