Question

Solve each equation by factoring.

1. m2-36=0
2. v2+7v-8=0
3. v2-9v=-8

Answer 1

1) \[a^{2}-b^{2} =(a+b)(a-b)\]
use this factorise

Answer 2

can u do it

Answer 3

Hmm, im still confused

Answer 4

\[m^{2}-6^{2}=0\]

Answer 5

ohh

Answer 6

(m+6)(m-6)=0

Answer 7

alright thanks!

Answer 8

what are the m values?

Answer 9

(-6,6)
right?

Answer 10

very good

Answer 11

Ok thank you very much

Answer 12

2) split the middle term

Answer 13

v2-1v+8v-8=0 ?

Answer 14

excellent

Answer 15

alright im just a bit confused on the last steps

Answer 16

v(v-1)+8(v-1)=0

Answer 17

r u clear

Answer 18

yep , thanks!

Answer 19

it would be (1, -8) ?

Answer 20

wait how would i do x2+x-56=0

Answer 21

can u do remaining part

Answer 22

yep, i'm all good now, thanks alot!

Answer 23

ok

Answer 24

when wait you split the equation how do you know which numbers go where, so like for p2+9p+18, it could be p2+6p+3p+18 or p2+3p+6p+18

Answer 25

u can write either way u will get same answer for both

Answer 26

\[3n^{2}-6n+n-2=0\]

Answer 27

is it clear

Answer 28

really? but say for instance the answer -6,- 3 on my answer sheet in my book it says -3, -6

Answer 29

it makes no difference
p= -3 or p= -6
p= -6 or p= -3
is there any difference

Answer 30

ohhh, okay wait nvm I see, i kept thinking it was (x, y) format